QA - HCF and LCM of Numbers
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Question 1 of 5
1. Question
1 pointsA farmer wants to plant 44 apples tree, 66 banana trees and 110 mango trees in equal rows (in terms of number of trees). Also, he wants to make distinct rows of tree (i.e. only one type of tree in one row). The number of rows (minimum) that required is
Correct
In such case, we first need to find the HCF of 44, 66 and 110
HCF = 22
Then, the required numbers of rows = {(44/22) + (66/22) + (110/22)} = 10Incorrect
In such case, we first need to find the HCF of 44, 66 and 110
HCF = 22
Then, the required numbers of rows = {(44/22) + (66/22) + (110/22)} = 10Unattempted
In such case, we first need to find the HCF of 44, 66 and 110
HCF = 22
Then, the required numbers of rows = {(44/22) + (66/22) + (110/22)} = 10 -
Question 2 of 5
2. Question
1 pointsIn a store there are 345 L mustard oil, 120 L olive oil and 225 L coconut oil. What will be the capacity of the largest container to measure the above three types of oil?
Correct
Required capacity of the largest container is the H.C.F of 345 , 120, 225 = 15
Therefore, the required capacity of the container is 15 LIncorrect
Required capacity of the largest container is the H.C.F of 345 , 120, 225 = 15
Therefore, the required capacity of the container is 15 LUnattempted
Required capacity of the largest container is the H.C.F of 345 , 120, 225 = 15
Therefore, the required capacity of the container is 15 L -
Question 3 of 5
3. Question
1 pointsJoseph visits the club on every 5th day, Harsh visits on every 24th day, while Sumit visits on every 9th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again ?
Correct
Joseph visits the club every 5th day. Harsh visits the club every 24th day. Sumit visits the club every 9th day. The next time they will meet again will be the LCM of these time-periods.
LCM (5, 24, 9) = 360
So, all the three will meet 360 days after Sunday.
Now, we need not count 360 days. Rather we will use the concept of odd days.
Odd number of days in 360 = Remainder when 360 is divided by 7 = 3
So, they will meet again on Sunday + 3 = WednesdayIncorrect
Joseph visits the club every 5th day. Harsh visits the club every 24th day. Sumit visits the club every 9th day. The next time they will meet again will be the LCM of these time-periods.
LCM (5, 24, 9) = 360
So, all the three will meet 360 days after Sunday.
Now, we need not count 360 days. Rather we will use the concept of odd days.
Odd number of days in 360 = Remainder when 360 is divided by 7 = 3
So, they will meet again on Sunday + 3 = WednesdayUnattempted
Joseph visits the club every 5th day. Harsh visits the club every 24th day. Sumit visits the club every 9th day. The next time they will meet again will be the LCM of these time-periods.
LCM (5, 24, 9) = 360
So, all the three will meet 360 days after Sunday.
Now, we need not count 360 days. Rather we will use the concept of odd days.
Odd number of days in 360 = Remainder when 360 is divided by 7 = 3
So, they will meet again on Sunday + 3 = Wednesday -
Question 4 of 5
4. Question
1 pointsTwo numbers are in the ratio of 3:4. Their L.C.M. is 84. Find the numbers.
Correct
Let the numbers be 3x and 4x. Then, their L.C.M. = 12x.
so, 12x = 84 (LCM is 84 – given)
x = 84/12
x = 7
Therefore, the numbers are 21 and 28.
Incorrect
Let the numbers be 3x and 4x. Then, their L.C.M. = 12x.
so, 12x = 84 (LCM is 84 – given)
x = 84/12
x = 7
Therefore, the numbers are 21 and 28.
Unattempted
Let the numbers be 3x and 4x. Then, their L.C.M. = 12x.
so, 12x = 84 (LCM is 84 – given)
x = 84/12
x = 7
Therefore, the numbers are 21 and 28.
-
Question 5 of 5
5. Question
1 pointsThe LCM of three different numbers is 120. Which of the following cannot be their HCF?
Correct
It is given that Lowest Common Multiple of three different numbers is 120. Thus, a HCF of those numbers must be a factor of that L.C.M. too. From the given options only 35 is not a factor of 120 and therefore it can’t be the H.C.F.
Incorrect
It is given that Lowest Common Multiple of three different numbers is 120. Thus, a HCF of those numbers must be a factor of that L.C.M. too. From the given options only 35 is not a factor of 120 and therefore it can’t be the H.C.F.
Unattempted
It is given that Lowest Common Multiple of three different numbers is 120. Thus, a HCF of those numbers must be a factor of that L.C.M. too. From the given options only 35 is not a factor of 120 and therefore it can’t be the H.C.F.
